Finish autocorrelation
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main.tex
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main.tex
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@ -522,6 +522,29 @@ var.ts <- 1/n^2*acf(b,lag=0,type="cov")$acf[1]*(n+2*sum(((n-1):(n-10))*acf(b,10)
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mean(b) + c(-1.96,1.96)*sqrt(var.ts)
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mean(b) + c(-1.96,1.96)*sqrt(var.ts)
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\end{lstlisting}
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\end{lstlisting}
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\subsection{Partial autocorrelation (PACF)}
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The $k$-th partial autocorrelation $\pi_k$ is defined as the correlation between $X_{t+k}$ and $X_t$, given all the values in between.
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$$\pi_k = Cor(X_{t+k},X_t | X_{t+1},...,X_{t+k-1} = x_{t+k-1})$$
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\begin{itemize}
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\item Given a time series X t , the partial autocorrelation of lag $k$, is the autocorrelation between $X_t$ and $X_{t+k}$ with the linear dependence of $X_{t+1}$ through to $X_{t+k-1}$ removed.
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\item One can draw an analogy to regression. The ACF measures the „simple“ dependence between $X_t$ and $X_{t+k}$, whereas the PACF measures that dependence in a „multiple“ fashion.\footnote{See e.g. \href{https://n.ethz.ch/~jannisp/download/Mathematik-IV-Statistik/zf-statistik.pdf}{\textit{Mathematik IV}}}
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\end{itemize}
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$$\pi_1 = \rho_1$$
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$$\pi_2 = \frac{\rho_2 - \rho_1^2}{1-\rho_1^2}$$
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for AR(1) moderls, we have $\pi_2 = 0$, because $\rho_2 = \rho_1^2$, i.e. there is no conditional relation between $(X_t, X_{t+2} | X_{t+1})$
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\begin{lstlisting}[language=R]
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pacf(wave, ylim=c(1,1))
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\end{lstlisting}
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\begin{figure}[H]
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\centering
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\includegraphics[width=.25\textwidth]{pacf.png}
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\caption{PACF for wave tank}
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\label{fig:pacf}
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\end{figure}
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\scriptsize
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\scriptsize
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\section*{Copyright}
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\section*{Copyright}
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@ -532,8 +555,8 @@ Jannis Portmann, FS21
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\section*{References}
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\section*{References}
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\begin{enumerate}
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\begin{enumerate}
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\item ATSA\_Script\_v219219.docx, M. Dettling
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\item ATSA\_Script\_v210219.docx, M. Dettling
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\item ATSA\_Slides\_v219219.pptx, M. Dettling
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\item ATSA\_Slides\_v210219.pptx, M. Dettling
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\end{enumerate}
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\end{enumerate}
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\section*{Image sources}
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\section*{Image sources}
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